SOLUTION: solve 2log(base e)(x) + log(base e)(7) = 1 please...
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Question 691403
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solve 2log(base e)(x) + log(base e)(7) = 1 please...
Answer by
nerdybill(7384)
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2log(base e)(x) + log(base e)(7) = 1
log(base e)(x^2) + log(base e)(7) = 1
log(base e)(7x^2) = 1
(7x^2) = e^1
x^2 = e/7
x = .6232