SOLUTION: Hello, I was needing help on this problem.... 5^(3x-1)=17 I was trying (3x-1)ln5=17???? Not sure how to set this up properly.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hello, I was needing help on this problem.... 5^(3x-1)=17 I was trying (3x-1)ln5=17???? Not sure how to set this up properly.      Log On


   



Question 691266: Hello,
I was needing help on this problem....
5^(3x-1)=17
I was trying (3x-1)ln5=17????
Not sure how to set this up properly.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
5^(3x-1)=17
-----------
Get the log of both sides
log%285%5E%283x-1%29%29+=+log%2817%29
then
5%5E%283x-1%29+=+log%2817%29
3x-1%29%2Alog%285%29+=+log%2817%29
3x-1+=+log%2817%29%2Flog%285%29
3x+=+1+%2B+log%2817%29%2Flog%285%29
x+=+1%2F3+%2B+log%2817%29%2F%283%2Alog%285%29%29