SOLUTION: Hello, I was needing help on this problem.... 5^(3x-1)=17 I was trying (3x-1)ln5=17???? Not sure how to set this up properly.
Algebra
->
Logarithm Solvers, Trainers and Word Problems
-> SOLUTION: Hello, I was needing help on this problem.... 5^(3x-1)=17 I was trying (3x-1)ln5=17???? Not sure how to set this up properly.
Log On
Algebra: Logarithm
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on logarithm
Question 691266
:
Hello,
I was needing help on this problem....
5^(3x-1)=17
I was trying (3x-1)ln5=17????
Not sure how to set this up properly.
Answer by
Alan3354(69443)
(
Show Source
):
You can
put this solution on YOUR website!
5^(3x-1)=17
-----------
Get the log of both sides
then