SOLUTION: how to solve this logarithmic equation: 8logx=2

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Question 691222: how to solve this logarithmic equation:
8logx=2
Answer by fcabanski(1391) About Me  (Show Source):
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8log(x)=2 divide both sides by 8 --->log(x) = 1/4 = .25.


Remember the log identity log(basea)(x) = y if and only if a^y = x.


log(x) = .25 is log base 10 (x) = .25 ---> 10^.25 = x. 10^.25 is approximately 1.778 so x = 1.778.

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