Question 690974:  Solve sin 2x = sin x for x between 0 and 2pi.  
 Answer by stanbon(75887)      (Show Source): 
You can  put this solution on YOUR website! Solve sin 2x = sin x for x between 0 and 2pi.  
---- 
2sin(x)cos(x) = sinx 
--- 
2sin(x)cos(x)-sin(x) = 0 
---- 
Factor: 
sin(x)[2cos(x)-1) = 0 
sin(x) = 0 or cos(x) = 1/2 
---- 
x = 0, or 2pi or pi/3 or (5/3)pi 
------------------------------------ 
cheers, 
Stan H. 
================== 
  | 
 
  
 
 |   
 
 |