SOLUTION: The length of a rectangle is 8 in, more than twice its width. If the perimeter of the rectangle is 64in, find the width of the rectangle. Please help

Algebra ->  Linear-equations -> SOLUTION: The length of a rectangle is 8 in, more than twice its width. If the perimeter of the rectangle is 64in, find the width of the rectangle. Please help      Log On


   

Question 69089: The length of a rectangle is 8 in, more than twice its width. If the perimeter of the rectangle is 64in, find the width of the rectangle.
Please help
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
width = w
length = 2w + 8
2*length + 2*width = perimeter
2(2w + 8) + 2(w) = 64
4w + 16 + 2w = 64
6w = 48
w = 8
width = 8in
length = 24in