Question 690646: ln(2x+1) + ln(x-3)- 2 lnx = 0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! ln(2x+1) + ln(x-3)- 2 lnx = 0
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ln[(2x+1)(x-3)/x^2] = 0
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(2x+1)(x-3)/x^2 = e^0
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(2x+1)(x-3)/x^2 = 1
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2x^2-5x-3 = x^2
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x^2 -5x -3 = 0
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x = [5 +- sqrt(25-4*-3)]/2
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x = [5 +- sqrt(37)]/2
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Positive solution:
x = (5/2) + (1/2)sqrt(37)
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Cheers,
Stan H.
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