SOLUTION: 2) Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following: a) What is r, the ratio between 2 consecutive terms? Answer: Show work in this space.

Algebra ->  Systems-of-equations -> SOLUTION: 2) Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following: a) What is r, the ratio between 2 consecutive terms? Answer: Show work in this space.       Log On


   



Question 69024: 2) Use the geometric sequence of numbers 1, 3, 9, 27, … to find the following:
a) What is r, the ratio between 2 consecutive terms?
Answer:
Show work in this space.



b) Using the formula for the nth term of a geometric sequence, what is the 10th term?
Answer:
Show work in this space.



c) Using the formula for the sum of a geometric series, what is the sum of the first 10 terms?
Answer:
Show work in this space.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a)
Since this series is geometric, there is a factor that you must multiply to get from term to term. To find this factor simply divide any nth term, n can be 2 in this case, and the previous term before it, n-1. So picking 3 as n and 1 as n-1 the ratio r is n%2Fn-1
So r=3%2F1=3 and it allows me to go from 3 to 9, 9 to 27, etc.
b)
Now that I know the ratio between two terms I can easily find any term that I want. Since I know that ratio is 3, this series is simply 3%5En, because any term involves multiplying 3's. So to find the tenth term, just plug in n=9 (the first term is zero) into 3%5En to get 3%5E9=19683 so the tenth term is 19683
c)
Instead of taking forever and deriving the formula, I'm just going to give it to you. I know it's a bad habit, but this seems a little advanced for algebra or geometry, so I have no idea of what level you're at. Also it not only takes a while to derive, but takes a lot of understanding as well, which should be reserved for a dedicated lesson. Anyway the sum of a geometric series to the nth term is:
S=a%281-r%5E%28n%2B1%29%29%2F%281-r%29 in this case a=1
So S=1%281-3%5E10%29%2F%281-3%29
S=%28-59048%29%2F%28-2%29
S=29524
If you want to verify this simply calculate all ten terms and add them all up, fun huh?