Technically, I can't answer your question. does not have any "solutions". The equation has two solutions, and the polynomial function has two zeros. But the way you asked it -- nope.
However, while I'm at it, I should mention that the quadratic equation has two roots, namely:
and
Adding these two roots you get:
Presuming you meant to state your problem correctly, you should be able to glean the required answer now.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
You can put this solution on YOUR website! Add the two solutions using the quadratic factoring equation:
(1) x1 + x2 = (-b + radical)/2a + (-b - radical)/2a or
(2) x1 + x2 = (-b-b)/2a + 0 , where the radical term sqrt(201) cancels
giving
(3) sum = -2b/2a or
(4) sum = -b/a
Using the values of a and b we get
(5) sum = -3/3 or
(6) sum of roots = -1
Answer: Choice B
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