Question 690228: Three sisters met for dinner at a restaurant. Their bill was $30. They divided the amount equally, and each paid $10. The cashier discovered that an error had been made in tabulating their bill. It should have been $25 instead of #30. The cashier informed the waiter of this error and gave in $5 to return to the sisters. On the way back to the table, the waiter decided to keep $2 and return $1 to each sister.
If each sister received $1 back, then each paid $10 - $1, or $9 for dinner, which is a total of $27! The waiter kept $2 which yields a total of $29! Where is the missing dollar?
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Three sisters met for dinner at a restaurant. Their bill was $30. They divided the amount equally, and each paid $10. The cashier discovered that an error had been made in tabulating their bill. It should have been $25 instead of #30. The cashier informed the waiter of this error and gave in $5 to return to the sisters. On the way back to the table, the waiter decided to keep $2 and return $1 to each sister.
If each sister received $1 back, then each paid $10 - $1, or $9 for dinner, which is a total of $27! The waiter kept $2 which yields a total of $29! Where is the missing dollar?
:
If the total bill was $25, then each should have paid 25/3 = $8.33, so each should have gotten 10-8.33 = $1.67 back, they each got only $1, short changed 67 cents,
that's 3*.67 ~ $2 the waiter kept
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