SOLUTION: 5+4i/4-i

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Question 690158: 5+4i/4-i
Found 2 solutions by solver91311, ReadingBoosters:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Multiply your fraction by 1 in the form of the conjugate of the denominator divided by itself.



Use FOIL. Remember, the product of two conjugates is the difference of two squares, but since , the product of two COMPLEX conjugates is the SUM of two squares.

John

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Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
%28%285%2B4i%29%2F%284-i%29%29%28%284%2Bi%29%2F%284%2Bi%29%29
...
%28%285%2B4i%29%284%2Bi%29%29%2F%28%284-i%29%284%2Bi%29%29
...
numerator 5%284%29+%2B+5i+%2B+16i+%2B+4i%5E2
20 + 21i + 4(-1) = 16+21i
denominator 16+-+i%5E2 = 16 - -1 = 17
highlight_green%28%2816%2B21i%29%2F17%29
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