SOLUTION: Two cyclists start toward each other from points 25 miles apart. Cyclist No. 1 travels 15 mph, while Cyclist No. 2 travels to 10 mph. A trained bird leaves the shoulder of cyclist
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Question 690101: Two cyclists start toward each other from points 25 miles apart. Cyclist No. 1 travels 15 mph, while Cyclist No. 2 travels to 10 mph. A trained bird leaves the shoulder of cyclist No. 1 and travels to the shoulder of Cyslist No.2 and forth until the cyclists meet. If the bird flies at 40 mph, how far will the bird fly? Answer by solver91311(24713) (Show Source):
The first cyclist will travel 10 miles in the first hour, and the second cyclist will travel 15 miles in that same hour. So together they will cover the original 25 mile difference in that hour and meet at that time. The bird will be flying at 40 miles per hour for that same hour.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
