SOLUTION: Hello, I was wondering how you would solve this equation. log base 5(x+3)=1 Thank you!

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Question 689700: Hello, I was wondering how you would solve this equation.
log base 5(x+3)=1
Thank you!
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
log%285%2C+%28x%2B3%29%29+=+1
Solving equations where the variable is in the argument of a logarithm usually starts with transforming the equation into one of the following forms:
log(expression) = number
or
log(expression) = log(expression)

Your equation is already in the first form. The next step with this form is to rewrite the equation in exponential form. In general log%28a%2C+%28p%29%29+=+q is equivalent to a%5Eq+=+p. Using this pattern on your equation:
5%5E1+=+x%2B3
The left side simplifies:
5+=+x%2B3
Subtracting 3:
2+=+x