SOLUTION: log5(x+6)+log5(X+2)=1
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Question 689425
:
log5(x+6)+log5(X+2)=1
Answer by
stanbon(75887)
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log5(x+6)+log5(X+2)=1
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log5[(x+6)(x+2)] = 1
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x^2+8x+12 = 5^1
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x^2 + 8x + 7 = 0
Factor:
(x+7)(x+1) = 0
x = -7 or x = -1
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Only x = -1 is an acceptable solution.
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Cheers,
Stan H.