Question 689301: Find the area between abs(x) and x^2/4
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find the area between abs(x) and x^2/4
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Both "functions are symmetrical about the y-axis.
The are enclosed if from (0,0) to (4,4) on the right side.
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Area between the x-axis and y = |x| = 4*4/2 = 8 sq units.
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INT(x^2/4) = x^3/12 (ignore the constant of integration)
At x = 4 --> 64/12 = 8/3 sq units
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Closed area = 8 - 8/3 = 16/3 sq units
Same on the left side
Total = 32/3 sq units.
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