Question 689131: Write the equation of the circle in standard form. Find the center, radius, intercepts, and graph the circle.
x^2+y^2-8x-6y+9=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Write the equation of the circle in standard form. Find the center, radius, intercepts, and graph the circle.
x^2+y^2-8x-6y+9=0
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Complete the square on the x-terms and on the y-terms:
x^2 - 8x + 16 + y^2 - 6y + 9 = 16
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(x-4)^2 + (y-3)^2 = 4^2
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Center: (4,3)
radius: 4
y-axis intercept: (0,3)
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x-axis intercepts ??
Let y = 0, then x^2 -8x + 9 = 0
(x-9)(x+1) = 0
x-axis intercepts: (9,0) and (-1,0)
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Cheers,
Stan H.
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