SOLUTION: I'm having a difficult time with the following problem and would greatly appreciate help. The problem reads: I plan to fence my rectangular garden with 100 meters of fencing. I

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Question 689122: I'm having a difficult time with the following problem and would greatly appreciate help. The problem reads: I plan to fence my rectangular garden with 100 meters of fencing. I am using the function A=w(50-w) to express the area in terms of its width. What is the maximum possible area that I can enclose with this fencing?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The maximum area of a rectangle always ends
up being a square when you alter the lengths
of the sides. I will show this for your problem.
+A+=+w%2A%28+50+-+w+%29+
+A+=+50w+-+w%5E2+
rewrite it
+A+=+-w%5E2+%2B+50w+
This is a parabola which has a maximum and
not a minimum. This is indicated by the minus sign
in front of the +w%5E2+ term
-------------------------
There are 2 equally valid ways to find the w-coordinate
of the peak ( maximum area ).
The peak will be midway between the roots which occur
when +A+=+0+
+A+=+w%2A%28+50+-+w+%29+
+0+=+w%2A%28+50+-+w+%29+
This equation is true for 2 values of +w+,
+w+=+0+, and +w+=+50+
The peak will be midway between, at +w+=+25+
------------------------------------------
The other way to find the maximum is to use the general
formula +x%5Bmax%5D+=+-b%2F%282a%29+ where the equation
has the form +y+=+ax%5E2+%2B+b%2Ax+%2B+c+. Of course you have
+w%5Bmax%5D+=+-b%2F%282a%29+
+A+=+a%2Aw%5E2+%2B+b%2Aw+ ( c = 0 )
You have
+a+=+-1+
+b+=+50+, so
+w%5Bmax%5D+=+-50%2F%282%28-1%29%29+
+w%5Bmax%5D+=+25+
--------------------
Now when you plug +w%5Bmax%5D+=+25+ back into your equation,
+A+=+-+w%5E2+%2B+50w+
+A+=+-+25%5E2+%2B+50%2A25+
+A+=+-625+%2B+1250+
+A+=+625+ which is the maximum area
Ntice that you have a square because
+2%2AL+%2B+2%2AW+=+C+ ( formula for circumference )
+2%2A25+%2B+2%2A25+=+C+
+50+%2B+50+=+100+ m of fencing
hope this helps