SOLUTION: Can someone please help me find the radius and center of the circle x^2+y^2-3x=39-6y. I have the center being (1.5,-3) and the radius 7.088723439378713 but not confident. Thank you
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-> SOLUTION: Can someone please help me find the radius and center of the circle x^2+y^2-3x=39-6y. I have the center being (1.5,-3) and the radius 7.088723439378713 but not confident. Thank you
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Question 689071: Can someone please help me find the radius and center of the circle x^2+y^2-3x=39-6y. I have the center being (1.5,-3) and the radius 7.088723439378713 but not confident. Thank you! Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Can someone please help me find the radius and center of the circle
x^2+y^2-3x=39-6y.
complete the square
x^2-3x+y^2+6y=39
(x^2-3x+9/4)+(y^2+6y+9)=39+9/4+9
(x-3/2)^2+(y+3)^2=50.25
center: (3/2,-3)
radius=√50.25≈7.0887..
you got it right!
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