SOLUTION: multiply (x^4+3)(x^4-5) and multiply (-2x-3)^2

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Question 68889: multiply (x^4+3)(x^4-5)
and
multiply (-2x-3)^2
Answer by rmromero(383) About Me  (Show Source):
You can put this solution on YOUR website!
(x^4+3)(x^4-5) 
FOIL METHOD 

Multiply F = First terms

Multiply O = Outer terms

Multiply I = Inner terms

Multiply L = Last terms



       (x^4 + 3)(x^4 - 5)          (x^4 + 3)(x^4 - 5) 

         |        |                  |             | 

         |        |                  |             |

       First    First              Outer         Outer



      (x^4 + 3)(x^4 - 5)           (x^4 + 3)(x^4 - 5) 

             |   |                        |        |

             |   |                        |        |

             Inner                       Last     Last

             



 

x%5E4+%28x%5E4%29+%2B+x%5E4%28-5%29%2B+3%28x%5E4%29+%2B+3%28-5%29



x%5E8+-+5x%5E4+%2B+3x%5E4+-+15        Simplify



x%5E8+-+2x%5E4+-+15               Combine like term







%28-2x-3%29%5E2

      |    | 

    base  Exponent



exponent indicates how many times you will multiply the base.



(-2x - 3)(-2x - 3)

Use FOIL Method

-2x(-2x) + (-2x)(-3) + (-3)(-2x) + (-3)(-3)

4x%5E2+%2B+6x+%2B+6x+%2B+9

Answer:

4x%5E2+%2B12x+%2B+9