SOLUTION: 2sin^2theta-5sintheta-3=0
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Question 688867
:
2sin^2theta-5sintheta-3=0
Answer by
lwsshak3(11628)
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for [0,2π)
2sin^2theta-5sintheta-3=0
2sin^2x-5sinx-3=0
(2sinx+1)(sinx-3)=0
2sinx+1=0
sinx=-1/2
x=5π/6 and 11π/6
or
sinx=3(no solution) -1 < sinx ≤ 1