SOLUTION: if sinθ = 8/17 and 0≤θ≤ π/2, find cosθ
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-> SOLUTION: if sinθ = 8/17 and 0≤θ≤ π/2, find cosθ
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Question 688620
:
if sinθ = 8/17 and 0≤θ≤ π/2, find cosθ
Answer by
jim_thompson5910(35256)
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sin^2 + cos^2 = 1
(8/17)^2 + cos^2 = 1
64/289 + cos^2 = 1
cos^2 = 1 - 64/289
cos^2 = 225/289
cos = sqrt(225/289)
cos = 15/17
So cosθ = 15/17