Question 688586: Sketch the graph of the parabola, determine the vertex, focus, axis and the directrix:
y^2=12x
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Sketch the graph of the parabola, determine the vertex, focus, axis and the directrix:
y^2=12x
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This is an equation of a parabola that opens rightwards.
Its standard form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
For given equation:y^2=12x
vertex:(0,0)
axis of symmetry: y=0 or x-axis
4p=12
p=3
focus:(3,0) (p-distance to the right of the vertex on the axis of symmetry)
directrix: x=-3 (p-distance to the left of the vertex on the axis of symmetry)
see graph below:
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