SOLUTION: {{{2x^2-5x-3>=0}}}

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Question 688478: 2x%5E2-5x-3%3E=0
Answer by ReadingBoosters(3246) About Me  (Show Source):
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2x%5E2-5x-3%3E=0
Where is the graph above the x axis?
...
First
Find factors of 2 and 3 which can be subtracted to yield -5
Factors of 2: 1, 2
Factors of 3: 1, 3
...
Adding -6 and 1 yields -5
...
%282x%2B1%29%28x-3%29%3E=0
...
2x+1=0
2x = -1
x=-1%2F2
AND
x-3=0
x=3
...
The line crosses at x = -1%2F2 and 3.
Either below -1%2F2, between -1%2F2 and 3, or above 3,
the graph is above the x axis.
...
Being a positive quadratic, where the parabola forms a "smile,"
it is above the x axis where
highlight_green%28x%3C=-1%2F2%29 AND highlight_green%28x%3E=3%29
...
Between -1%2F2 and 3, the parabola is below the x axis
...
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C2x%5E2-5x-3%29
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