SOLUTION: Directions: Solve each of the following quadratic equations. Problem# 24 4x^2 = 13x +12 Directions: Solve the following problem Problem# 48 Geometry. If the sides of

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Directions: Solve each of the following quadratic equations. Problem# 24 4x^2 = 13x +12 Directions: Solve the following problem Problem# 48 Geometry. If the sides of      Log On


   

Question 68834: Directions: Solve each of the following quadratic equations.
Problem# 24
4x^2 = 13x +12

Directions: Solve the following problem
Problem# 48
Geometry. If the sides of a square are decreased by 2cmm the area is decreased by 36cm^2. What were the dimensions of the original square?
Found 2 solutions by checkley71, rapaljer:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
4x^2=13x+12
4x^2-13x-12=0
(4x-3)(x+4)=0
4x-3=0
4x=3
x=3/4 answer
x+4=0
x=-4 answer

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
The solution by the other tutor is WRONG!!

4x^2 = 13x +12
4x^2 - 13x -12=0
(4x +3)(x-4) = 0
The first solution is:
4x= -3
x=+-3%2F4

The second solution is
x=4

R^2 at SCC