SOLUTION: Please help me simplify for this equation: {{{ 3 square root of 8a^12 }}}. The 3 is small outside to the left of square root of 8a^12

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Question 68822: Please help me simplify for this equation: +3++square+root++of+8a%5E12+.
The 3 is small outside to the left of square root of 8a^12
Found 2 solutions by rmromero, ankor@dixie-net.com:
Answer by rmromero(383) About Me  (Show Source):
You can put this solution on YOUR website!
+3++square+root++of+8a%5E12+.
Since it involves cube root, we are going to find prime factors of 8 and a^12
8 = 2*2*2
= 2^3
a^12 = a*a*a*a*a*a*a*a*a*a*a*a
= a^3*a^3*a^3*a^3
= (a^3)^4
Therefore the cube root of 8a^12 is 2a^4

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
I think you mean:
:
CubeRt(8*a^12)
:
Think of this as factored to
:
CubeRt[2*2*2*a^4*a^4*a^4]
:
Extracting the cube root gives you:
:
2*a^4
:
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