Question 688187: A five-member student committee is to be selected from 12 students.
a) How many different 4-person committees are possible?
b) What is the probability that Joyce, Jasmine, Jessica and Clifford (not in any order) are members of the committee?
c) What is the probability that Joyce, Jasmine, Jessica and Clifford (in that given order) are members of the committee?
Thanks in advance for the help everyone!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A five-member student committee is to be selected from 12 students.
a) How many different 4-person committees are possible?
Ans: 12C4 = (12*11*10*9)/(1*2*3*4) = 495
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b) What is the probability that Joyce, Jasmine, Jessica and Clifford (not in any order) are members of the committee?
Only one group of 4 contains all of those folks.
Ans: 1/495
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c) What is the probability that Joyce, Jasmine, Jessica and Clifford (in that given order) are members of the committee?
# of orders of length 4: 12P4 = 12!/(8!) = 12*11*10*9 = 11880
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Ans: P(1/11880)
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Cheers,
Stan H.
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