Question 688182: Dear Sir/ Madam a pleasant day! please help me with a word problem about joint variation, I am not sure whether my answer is right or wrong.
If y varies jointly as x and the square root of z, and inversely as the cube of w, and y = 8 when x=3, z=16 and w=2, find y when x=5, z=25 and w=2.
I answered 8/133.33, please help me and thank you so much!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If y varies jointly as x and the square root of z,
and inversely as the cube of w,
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y = k*x*sqrt(z)/w^3
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Solve for "k" using "y = 8 when x=3, z=16 and w=2"
8 = k*3*4/2^3
8 = k(3/2)
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k = 16/3
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Equation:
y = (16/3)*x*sqrt(z)/w^3
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Find y when x=5, z=25 and w=2.
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y = (16/3)*5*5/8
y = (2/3)25
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y = 16 2/3
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Cheers,
Stan H.
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