SOLUTION: Infinite Sets: for the following arithmetic sequence 1) Find the specified term "a n" (n is located to the right of a but lower) 2) Find the sum of the terms from a1 to an, incl

Algebra ->  Finite-and-infinite-sets -> SOLUTION: Infinite Sets: for the following arithmetic sequence 1) Find the specified term "a n" (n is located to the right of a but lower) 2) Find the sum of the terms from a1 to an, incl      Log On


   



Question 687900: Infinite Sets:
for the following arithmetic sequence 1) Find the specified term "a n" (n is located to the right of a but lower) 2) Find the sum of the terms from a1 to an, inclusive.
5,9,13,17,...;find a10 (a then the 10 on right side of a but lower, opposite of an exponent)
There just doesn't seem to be a way to type the problems correctly. PLEASE HELP!

Answer by MathTherapy(10556) About Me  (Show Source):
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Infinite Sets:
for the following arithmetic sequence 1) Find the specified term "a n" (n is located to the right of a but lower) 2) Find the sum of the terms from a1 to an, inclusive.
5,9,13,17,...;find a10 (a then the 10 on right side of a but lower, opposite of an exponent)
There just doesn't seem to be a way to type the problems correctly. PLEASE HELP!

5, 9, 13, 17

This is an arithmetic sequence, or arithmetic progression (AP), as the first term begins with the number 5, and each term thereafter is found by adding 4 to the previous term.

Formula for AP: a%5Bn%5D+=+a%5B1%5D+%2B+%28n+-+1%29d, with a%5Bn%5D being the required term, n being the term number, a%5B1%5D being the 1st term, and d being the difference between each term.

In this case, a%5Bn%5D+=+a%5B10%5D, a%5B1%5D+=+5, n+=+10, and d++=+4

Therefore, a%5Bn%5D+=+a%5B1%5D+%2B+%28n+-+1%29d becomes: a%5B10%5D+=+5+%2B+%2810+-+1%294, or a%5B10%5D+=+5+%2B+%289%294, or a%5B10%5D+=+5+%2B+36, or highlight_green%28a%5B10%5D+=+41%29



Formula for sum of the series, a%5B1%5D to a%5B10%5D = S%5Bn%5D+=+%28n%2F2%29%282a%5B1%5D+%2B+%28n+-+1%29%29d

S%5B10%5D+=+%2810%2F2%29%282%285%29+%2B+%2810+-+1%29%294 ------ Substituting S%5B10%5D for S%5Bn%5D, 10 for n, 5 for a%5B1%5D, and 4 for d

S%5B10%5D+=+5%2810+%2B+%289%294%29

S%5B10%5D+=+5%2810+%2B+36%29

S%5B10%5D+=+5%2846%29

S%5B10%5D, or the sum of the 1st ten numbers in the series = highlight_green%28230%29

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