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Question 6879: It has been over 24 years since I have used algebra. I have 2 days until I take a test for an electrition apperentiship. I have to take a simple algebra test. One of the questions is
A=B+3(4-C)
B=5 and C=2
What is the value of A
I know the anwser is 11 (according to the back of the book anwsers)
My question is, how do they get that anwser? I remember that you do the work in the () first which would be (4-2)which would equal 2
so A=B+3(2)
A=5+3(2)
A=8(2)
A=10
Which is not what they say it is.
Could you please tell me where I went wrong in my solving this question and some basic "this is what you do first" type of help.
Thank you,
Ron
Answer by glabow(165)   (Show Source):
You can put this solution on YOUR website! The rules for evaluating expressions is to do all raising to powers (and taking roots) first. You don't have any of these to contend with.
Second, you do all multiplication and division, first within any groups in parentheses and then left to right.
Third, you do all addition and subtraction, again left to right.
(Actually, left to right isn't necessary, but it's a good habit to get into.)
In your case, you need to multiply the 3(2) (giving 6) before you do the addition.
The final answer will surprise you. (By the way, when you did the addition first you got 8(2) which is 16. Numbers written one after the other means you multiply them. The parentheses are there to show that the number isn't 82.)
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