You can put this solution on YOUR website! the base of an isoceles triangle is 10cm and one of its sides is 8cm find the area of the triangle.
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Draw an isoceles triangle.
Label the base "10".
Label one of the sides 8
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Label the other side 8 because the sides are equal.
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Draw an altitude down from the vertex to the base.
It is a perpendicaular-bisector of the base.
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Each section of the base is now "5".
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Use Pythagoras to find the height:
8^2 = 5^2 + h^2
h = sqrt[64-25] = sqrt(39)
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Area = (1/2)(base)(height)
= (1/2)(10)*sqrt(39) is approximately 31.22 sq cm
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Cheers,
Stan H.
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