SOLUTION: Solve the equation {{{ log( 2x ) }}} = 1 + {{{ log(2) }}} (x+112)

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Solve the equation {{{ log( 2x ) }}} = 1 + {{{ log(2) }}} (x+112)      Log On


   

Question 687572: Solve the equation +log%28+2x+%29+ = 1 + +log%282%29+ (x+112)
Found 2 solutions by stanbon, MathTherapy:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
log2(x) + 1 = log2(x+112)
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log2(x+112) - log2(x) = 1
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log2[(x+112)/x] = 1
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(x+112)/x = 2
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x + 112 = 2x
x = 112
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Cheers,
Stan H.
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Cheers,
Stan H.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Solve the equation +log%28+2x+%29+ = 1 + +log%282%29+ (x+112)

If log%282%2C+%28x%29%29+=+1+%2B+log%282%2C+%28x+%2B+112%29%29, then x+=+-+224, and therefore, NO SOLUTION.