Question 687560: solve for n
c= 1/9 pie m^2n
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve for n
c= 1/9 pie m^2n
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9c = (pi)*m^(2n)
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m^(2n) = (9c)/(pi)
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Take the log to solve for "n":
2n*log(m) = (9c)/(pi)
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n = (9c)/(2(pi)*log(m)
n = (9c)/(log [m^(2pi)]
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Cheers,
Stan H.
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