SOLUTION: I need help solving this I have tried it for about 20 mins now! Log (3x-1+log2=log4+log(x+2))

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Question 687295: I need help solving this I have tried it for about 20 mins now!
Log (3x-1+log2=log4+log(x+2))
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Log (3x-1+log2=log4+log(x+2)
The parentheses are not right.
If you mean:
Log(3x-1) + log(2) = log(4)+log(x+2)
log(2*(3x-1)) = log(4*(x+2))
2*(3x-1) = 4*(x+2)
6x-2 = 4x+8
x = 5