Question 687244: For the function g(x) = 1/x-4 + 2:
Write the equations of the asymptotes and label them on the coordinate plane.
Enter at least five values in the table of values.
Graph the function on the coordinate plane.
Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! I believe you mean g(x) = 1/(x-4) + 2,
which I can write as
.
The function is sort of an ancestor of your function.
It has the x- and y-axes for asymptotes.
The y-axis, is a vertical asymptote
because the function does not exist for (it is not continuous at )
but as you approach , from either side,
grows without bounds.
The horizontal x-axis, , is an asymptote because as grows larger (at both ends of the x-axis),
approaches zero.
The function 
is the same, but moved 4 units to the right, a closer ancestor.
Its asymptotes are .
(vertical asymptote, where the function is not continuous), and
(again).
Adding to that function gives you .
The graph is 
and the asymptotes are and
.
Just five points seems too little for this function, but the symmetry might help.
For , .
(Symmetrically, for , .
For , .
(Symmetrically, for , .
For , .
(Symmetrically, for , .
For , .
(Symmetrically, for , .
For , .
(Symmetrically, for , .
We can plot those points as blue dots and connect them.
We can draw the asymptotes in green too.
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