Question 687062: Some material is placed in a store with variable humidity,resulting in various degrees of wetness of the material.Both humidity and moisture content are measured as percentages with the following results:
Humidity,x: 42 35 50 43 48 62 31
Moisture content,y: 2 8 14 9 11 16 7
Use the method of least squares to find a regression line, and use this line to estimate the moisture content when the humidity is 55%.Give a 95% Confidence interval for this estimate.
I am trying to solve it for many days now,but I cannot.
Thank you.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Some material is placed in a store with variable humidity,resulting in various degrees of wetness of the material.Both humidity and moisture content are measured as percentages with the following results:
Humidity,x: 42 35 50 43 48 62 31
Moisture content,y: 2 8 14 9 11 16 7
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Use the method of least squares to find a regression line, and use this line to estimate the moisture content when the humidity is 55%.
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I used the linear regression function on my TI-84 to get:
y = 0.34x - 5.34
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f(55) = 13.118
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Give a 95% Confidence interval for this estimate.
I'll leave this to you.
Cheers,
Stan H.
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