SOLUTION: Dear Sir, Q: If sin A=x^2-2x+2, Find Cos A I have tried this way sin^2 A = (x^2-2x+2)^2 1-cos^2 A= (x^2-2x+2)^2 Cos^2 A= 1-(x^2-2x+2)^2 Cos^2 A= 1^2-(x^2-2x+2)^2 = [1+(

Algebra ->  Trigonometry-basics -> SOLUTION: Dear Sir, Q: If sin A=x^2-2x+2, Find Cos A I have tried this way sin^2 A = (x^2-2x+2)^2 1-cos^2 A= (x^2-2x+2)^2 Cos^2 A= 1-(x^2-2x+2)^2 Cos^2 A= 1^2-(x^2-2x+2)^2 = [1+(      Log On


   

Question 686909: Dear Sir,
Q: If sin A=x^2-2x+2, Find Cos A
I have tried this way
sin^2 A = (x^2-2x+2)^2
1-cos^2 A= (x^2-2x+2)^2
Cos^2 A= 1-(x^2-2x+2)^2
Cos^2 A= 1^2-(x^2-2x+2)^2 = [1+(x^2-2x+2)][1-(x^2-2x+2)]
is it correct or am going somewhere wrong?
Kindly help me to solve this.
Regards,
AN
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Just take the sqrt of both side to get CosA. You could expand more, and possibly simplify, but I wouldn't. In fact, I would have stopped one step earlier and just taken then sqrt of 1-(x^2-2x+2)^2