|
Question 686744: suppose a parabola has an axis of symmetry at x=8, a maximum height of 1 and also passes through the point (9,-1). write the equation of the parabola in vertex form.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! suppose a parabola has an axis of symmetry at x=8, a maximum height of 1 and also passes through the point (9,-1). write the equation of the parabola in vertex form.
**
This is a parabola that opens downwards.
Its standard form of equation: (x-h)^2=-4p(y-k), (h,k)=(x,y) coordinates of the vertex
For given parabola:
vertex: (8,1)
(x-8)^2=-4p(y-1)
solve for 4p using coordinates of given point (9,-1)
(9-8)=4p(-1-1)
1=4p(-2)
4p=-1/2
equation of given parabola:
(x-8)^2=-(y-1)/2
|
|
|
| |
