SOLUTION: The length of a rectangle is twice the width. The perimeter is 36 feet. Find the length and width. Unknowns: ___________ _ = width ___________

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Question 686489: The length of a rectangle is twice the width. The perimeter is 36 feet. Find the length and width.
Unknowns: _____________ = width
_____________ = length
Write and equation and solve: (Remember that perimeter is 2l + 2w.)
Width = _________
Length = _________
Please help me with this problem. It was in my book & I don't know how to solve it. The whole book is full of these types of word problems.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is twice the width.
The perimeter is 36 feet. Find the length and width.
Unknowns:
______x_______ = width
______2x_______ = length
--------------------------------------------
Write and equation and solve: (Remember that perimeter is 2l + 2w.)
----
Perimeter = 2(length + width)
36 = 2(2x + x)
18 = 3x
x = 6
--------
Width = x = 6 feet
------
Length = 2x = 12 feet
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Cheers,
Stan H.
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SOLUTION: The length of a rectangle is twice the width. The perimeter is 36 feet. Find the length and width. Unknowns: ___________ _ = width ___________ _ = length Write and