Question 686473: This is about Gauss/Jordan Elimination.What are the value of x,y,w and z in the given equation: x+2y-w+z=9 2x-y+2w+3z=-3 3x+y+w-z=-4 x-y-3w+z=4
Answer by Edwin McCravy(20055) (Show Source):
You can put this solution on YOUR website! x+2y-w+z=9 2x-y+2w+3z=-3 3x+y+w-z=-4 x-y-3w+z=4
Put in all the 1's
Erase the letters and the plus signs,
put a bar where the equal signs are,
and put the whole thing in parentheses:
The idea is to get all 0's below the diagonal.
Caution:
1. After you've finished getting zeros under the diagonal
in column 1, NEVER USE ROW 1 AGAIN!
2. After you've finished getting zeros under the diagonal
in column 2, NEVER USE ROW 2 AGAIN!
Multiply the Row 1 by -2
Add Row 1 to Row 2
Divide Row 1 by -2
Multiply Row 1 by -3
Add Row 1 to Row 3
Divide Row 1 by -3
Multiply Row 1 by -1
Add Row 1 to row 4
Divide Row 1 fo -1
Multiply row 2 by -1
Add row 2 to row 3
Multiply Row 2 by 3 and Row 4 by 5
Add Row 2 to Row 4
Swap rows 3 and 4
Now we have only 0's under the diagonal,
so we put the letters and the equal signs back in-
Erase all the 0's and the 1's
Solve the 4th equation for z
Substitute into the 3rd equation and solve for w
Substitute and into the 2nd
equation and solve for y:
Substitute , , and
So the solution is (x,y,w,z) = (-1,3,-2,2)
Edwin
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