SOLUTION: Lucy took three tests. If her median score was 82, her mean score was 87, and the range was 17, what were her three test scores? My work so far: 87 = (82 + B + C) ÷ 3 87 × 3 =

Algebra ->  Probability-and-statistics -> SOLUTION: Lucy took three tests. If her median score was 82, her mean score was 87, and the range was 17, what were her three test scores? My work so far: 87 = (82 + B + C) ÷ 3 87 × 3 =      Log On


   



Question 686427: Lucy took three tests. If her median score was 82, her mean score was 87, and the range was 17, what were her three test scores?
My work so far:
87 = (82 + B + C) ÷ 3
87 × 3 = (82 + B + C)
261 = 82 + B + C
261 – 82 = B + C
170 = B + C

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Lucy took three tests. If her median score was 82, her mean score was 87, and the range was 17, what were her three test scores?
let three tests be a, b, and c
the median (being the middle value, in your case b)score was 82:
82=b......................1

the mean (average) was 87:
87=(a+b+c)/3...................2
and the range ( the difference between the two most extreme values)was 17:
let’s a%3Eb%3Ec
so. the range is the difference between a and c

17=a-c.......................3
______________________________
solve the system:
82=b......................1.......plug it in 2
87=(a+b+c)/3...................2
17=a-c.......................3
_________________
87=(a+82+c)/3...................2a
take 3 and solve for c
17=a-c.......................3
c=a-17...................plug it in 3a


87=%28a%2B82%2Ba-17%29%2F3...................2a.......solve for a
87%2A3=2a%2B82-17
261=2a%2B65
261-65=2a
196%2F2=a
a=98
now, go to 3a and find c

c=a-17
c=98-17
c=81

so, her three test scores a=98,b=82, and c=81