SOLUTION: Please help me solve this equation: Solve: log2 (x+5) + log2 (x+1) = 5

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Question 686407: Please help me solve this equation:
Solve: log2 (x+5) + log2 (x+1) = 5

Found 2 solutions by lynnlo, MathTherapy:
Answer by lynnlo(4176) About Me  (Show Source):
You can put this solution on YOUR website!
log(x+1)/log 2 +log*x+5)/log(2)=5

Answer by MathTherapy(10806) About Me  (Show Source):
You can put this solution on YOUR website!
Please help me solve this equation:

Solve:  log2 (x+5) + log2 (x+1) = 5
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The following response from the other person doesn't do much to answer this problem, or help
the "POSTER: "log(x+1)/log 2 +log*x+5)/log(2)=5"

log+%282%2C+%28x+%2B+5%29%29+%2B+log+%282%2C+%28x+%2B+1%29%29+=+5, with x > - 1
       log+%282%2C+%28%28x+%2B+5%29%28x+%2B+1%29%29%29+=+5 ------ Applying log+%28b%2C+%28c%29%29+%2B+log+%28b%2C+%28d%29%29 = log+%28b%2C+%28c%2Ad%29%29
          log+%282%2C+%28x%5E2+%2B+6x+%2B+5%29%29+=+5
                      x%5E2+%2B+6x+%2B+5+=+2%5E5 ---- Converting to EXPONENTIAL form
                      x%5E2+%2B+6x+%2B+5+=+32
                    x%5E2+%2B+6x+-+27+=+0
                (x - 3)(x + 9) = 0
                               x - 3 = 0     or      x + 9 = 0 ---- Setting each FACTOR equal to 0
                                     x = 3    or              x = - 9 (IGNORE)

The above x-value, - 9, is IGNORED because x MUST be > - 1, and x = - 9 is CLEARLY NOT!

So, only VALID/ACCEPTABLE solution is: x = 3