Question 685703: what is x when 16^x = 1/sq root of 2?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! what is x when 16^x = 1/sq root of 2?
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Establish the same base on both sides:
(2^4)^x = 1/(2^(1/2))
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2^(4x) = 2^(-1/2)
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Since the bases are the same, the exponents are equal.
4x = -1/2
x = -1/8
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Cheers,
Stan H.
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