Question 685658: Solve for x.
A). log(5x)-log(x+1)=4
B). -logbase6(4x+7)+logbase6(x)=1
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A). log(5x)-log(x+1)=4
log[5x/(x+1)] = 4
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5x/(x+1) = 10^4
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5x = 10,000x + 10,000
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9995x = -10,000
x = -1.0005
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But x cannot be negative, as then, 5x would be negative.
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Conclusion: No solution.
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B). -logbase6(4x+7)+logbase6(x)=1
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log6[x/(4x+7)] = 1
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x/(4x+7) = 6
x = 24x+42
23x = -42
x = -1.828
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But x cannot be negative, as then, log6(x) would be meaningless.
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Conclusion: No solution
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Cheers,
Stan H.
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