SOLUTION: The product of two consecutive odd integers is 21 less than 6 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first
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Question 685556: The product of two consecutive odd integers is 21 less than 6 times their sum. Find the two integers. Answer in the form of paired points with the lowest of the two integers first Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the integers be x & x+2
x(x+2) = 6(x+x+2)-21
x^2+2x=12x+12-21
x^2-10x+9=0
x^2-9x-x+9=0
x(x-9)-1(x-9)=0
(x-1)(x-9)=0
x=1 OR 9
the integers are 1,3
