SOLUTION: vertex of f(x)=x^2-2

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Question 685478: vertex of f(x)=x^2-2
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=x^2-2

f(x)=1(x-0)^2 + (-2)

So the vertex is (0,-2)