Question 68538: y = 2x^2 - 4x. for each function give the equation of the exis of symmetry, the coordinates of the vertex and the x- and y- intercepts of its graph
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! y = 2x^2 - 4x. for each function give the equation of the axis of symmetry, the coordinates of the vertex and the x- and y- intercepts of its graph
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y=2(x^2-2x)
Complete the square as follows:
2(x^2-2x+1)=y+2
2(x-1)^2 = y+2
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Vertex: (1,-2)
Axis of symmetry: x=1
y-intercept: (0,0) Get this from the original equation; let x=0, then y=0.
x-intercept: From original; let y=0, then 2x(x-2)=0;(0,0),(2,0) x-intercepts.
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Cheers,
Stan H.
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