SOLUTION: This equation involves more than one exponential expression. Solve the equation. Round approximate solutions to four decimal places. This is a logarithm problem.
6^x = 3^x+1
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-> SOLUTION: This equation involves more than one exponential expression. Solve the equation. Round approximate solutions to four decimal places. This is a logarithm problem.
6^x = 3^x+1
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Question 685188: This equation involves more than one exponential expression. Solve the equation. Round approximate solutions to four decimal places. This is a logarithm problem.
6^x = 3^x+1 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 6^x = 3^x+1
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Take the log of both sides to get:
x*log(6) = (x+1)log(3)
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x[log(6)-log(3)] = log(3)
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x = log(3)/[log(6/3)]
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x = log(3)/log(2)
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x = 1.585..
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cheers,
Stan H.
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