SOLUTION: Hi! How would I solve each equation for x a. 3^x=1/9 b. 2^3x=1/16 c.4^x=64 4^x=4^3

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Hi! How would I solve each equation for x a. 3^x=1/9 b. 2^3x=1/16 c.4^x=64 4^x=4^3       Log On


   

Question 684982: Hi! How would I solve each equation for x
a. 3^x=1/9 b. 2^3x=1/16 c.4^x=64
4^x=4^3
x=3
I was able to solve c but I don't know how I would do a and b
Thanks :)
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
a.
3%5Ex+=+1%2F9
1%2F9+=+1%2F3%5E2+=+3%5E-2
x = -2
...
b.
2%5E%283x%29+=+1%2F16
1%2F16+=+1%2F2%5E4+=+2%5E-4
3x = -4
x+=+-4%2F3
...
.....................
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