SOLUTION: solve algebraically and solve: absolute value of (3x+1) less than (x-11)

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Question 684767: solve algebraically and solve:
absolute value of (3x+1) less than (x-11)

Answer by mathbird(71) About Me  (Show Source):
You can put this solution on YOUR website!
|(3x+1)| < (x-11)
3x+1<(x-11);3x+1<-(x-11)
3x+1-1 3x 3x-x 2x<-12
dividing 2 on both sides
x<-6
now for 3x+1<-(x-11)
3x+1<-x+11
3x<-x+11-1
3x+x<10
4x<10
dividing 4 on both sides
x<10/4
x<5/2