Question 684501: A panel of 5 politicians is to be chosen from a group of 15 politicians
a) In how many ways can the panel be chosen?
Now suppose that the group of politicians consists of 8 Democrats, 4 Republicans, and 3 Independents. In how many ways can the panel of 5 politicians be chosen if the panel must consist of 2 Democrats, 2 Republicans, and 1 Independent?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A panel of 5 politicians is to be chosen from a group of 15 politicians
a) In how many ways can the panel be chosen?
Ans: 15C5 = (15*14*13*12*11)/(1*2*3*4*5) = 3003
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Now suppose that the group of politicians consists of 8 Democrats, 4 Republicans, and 3 Independents.
In how many ways can the panel of 5 politicians be chosen if the panel must consist of 2 Democrats, 2 Republicans, and 1 Independent?
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Ans: 8C2*4C2*3C1 = 28*6*3 = 504 ways
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Cheers,
Stan H.
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