SOLUTION: Find the equation of a straight line l1 which is perpendicular to l2:2x+3y-1=0 at the meeting point of l2 with the y-axis.
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Question 684340: Find the equation of a straight line l1 which is perpendicular to l2:2x+3y-1=0 at the meeting point of l2 with the y-axis. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find the equation of a straight line l1 which is perpendicular to l2:2x+3y-1=0 at the meeting point of l2 with the y-axis.
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Determine the slope of the given line:
2x + 3y - 1 = 0
3y = -2x+1
y = (-2/3)x + (1/3)
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Slope = -2/3
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Any line perpendicular to it must have a slope of 3/2
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Equation Form: y = mx + b
You know m = 3/2 and y = 0 when x = 12
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Solve for "b":
0 = (3/2)12 + b
b = -18
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Equation:
y = (3/2)x - 18
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Cheers,
Stan H.
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